0.2x^2-10x+400=0

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Solution for 0.2x^2-10x+400=0 equation: 



0.2x^2-10x+400=0

a = 0.2; b = -10; c = +400;
Δ = b2-4ac
Δ = -102-4·0.2·400
Δ = -220
Delta is less than zero, so there is no solution for the equation

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